이 문제는 두 power series를 나누는 프로시저를 구현하는 문제입니다.
이는 분모에 오는 수열의 역수를 구한 뒤 이 둘을 곱하면 됩니다.

잘 되는군요.^^
확인하는데 쓰인 수식은 책에 나오듯이 tangent와 1/(1-x)입니다.
특히 1/(1-x)를 만들 때 분자는 sin²x + cos²x을,
분모에는 ones의 덧셈 역원을 더하여 0의 스트림을 구현하였습니다.
그렇게 복잡하게 만들었음에도 잘 나오더군요.^^

MATLAB에서 tangent의 power series를 확인해보니 결과가 동일합니다.^^
참조
해럴드 애빌슨, 김재우 역, <컴퓨터 프로그램의 구조와 해석>, 인사이트, 2007, pp. 435
; stream
(define true (= 0 0))
(define false (= 1 0))
(define (cons-stream a b)
(cons a (delay b)))
(define the-empty-stream '())
(define stream-null? null?)
(define (stream-car stream) (car stream))
(define (stream-cdr stream) (force (cdr stream)))
; section 3.5
(define (stream-ref s n)
(if (= n 0)
(stream-car s)
(stream-ref (stream-cdr s) (- n 1))))
(define (stream-for-each proc s)
(if (stream-null? s)
'done
(begin (proc (stream-car s))
(stream-for-each proc (stream-cdr s)))))
(define (display-stream s)
(stream-for-each display-line s))
(define (display-line x)
(newline)
(display x))
(define (stream-enumerate-interval low high)
(if (> low high)
the-empty-stream
(cons-stream
low
(stream-enumerate-interval (+ low 1) high))))
(define (stream-filter pred stream)
(cond ((stream-null? stream) the-empty-stream)
((pred (stream-car stream))
(cons-stream (stream-car stream)
(stream-filter pred
(stream-cdr stream))))
(else (stream-filter pred (stream-cdr stream)))))
(define (memo-proc proc)
(let ((already-run? false) (result false))
(lambda ()
(if (not already-run?)
(begin (set! result (proc))
(set! already-run? true)
result)
result))))
(define (scale-stream stream factor)
(stream-map (lambda (x) (* x factor)) stream))
; exercise 3.50
(define (stream-map proc . argstreams)
(if (stream-null? (car argstreams))
the-empty-stream
(cons-stream
(apply proc (map stream-car argstreams))
(apply stream-map
(cons proc (map stream-cdr argstreams))))))
;;;SECTION 3.5.2
(define (add-streams s1 s2)
(stream-map + s1 s2))
(define ones (cons-stream 1 ones))
(define integers (cons-stream 1 (add-streams ones integers)))
; exercise 3.54
(define (mul-streams s1 s2)
(stream-map * s1 s2))
; exercise 3.56
(define (merge s1 s2)
(cond ((stream-null? s1) s2)
((stream-null? s2) s1)
(else
(let ((s1car (stream-car s1))
(s2car (stream-car s2)))
(cond ((< s1car s2car)
(cons-stream s1car (merge (stream-cdr s1) s2)))
((> s1car s2car)
(cons-stream s2car (merge s1 (stream-cdr s2))))
(else
(cons-stream s1car
(merge (stream-cdr s1)
(stream-cdr s2)))))))))
; print-stream-n
(define (print-stream-n S n)
(define (iter i)
(if (= i n)
'done
(begin (display (stream-ref S i))
(display " ")
(if (= (remainder (+ i 1) 10) 0)
(newline))
(iter (+ i 1)))))
(iter 0))
; exercise 3.59
(define (div-streams s1 s2)
(stream-map / s1 s2))
(define (integrate-series coff_stm)
(let ((integrate_s (cons-stream 1 ; 상수 c
(div-streams coff_stm integers))))
(stream-cdr integrate_s)))
(define exp-series
(cons-stream 1 (integrate-series exp-series)))
(define cosine-series
(cons-stream 1
(integrate-series (scale-stream sine-series -1))))
(define sine-series
(cons-stream 0
(integrate-series cosine-series)))
; exercise 3.60
(define (mul-series s1 s2)
(cons-stream (* (stream-car s1) (stream-car s2))
(add-streams (mul-series (stream-cdr s1) s2)
(scale-stream (stream-cdr s2) (stream-car s1)))))
; exercise 3.61
(define (invert-unit-series S)
(define X
(cons-stream 1
(scale-stream (mul-series (stream-cdr S) X) -1)))
X)
; exercise 3.62
; s1 / s2
(define (div-series s1 s2)
(if (= 0 (stream-car s2))
(error "Divide by zero" s2)
(mul-series s1 (invert-unit-series s2))))
; execute
(define f1 (div-series sine-series cosine-series))
(print-stream-n cosine-series 10)
(print-stream-n sine-series 10)
(print-stream-n f1 10)
(newline) (newline)
(define constant_one
(add-streams (mul-series sine-series sine-series)
(mul-series cosine-series cosine-series)))
(define one_minus_x
(cons-stream 1
(cons-stream -1
(add-streams ones
(scale-stream ones -1)))))
(define f2 (div-series constant_one one_minus_x))
(print-stream-n constant_one 10)
(print-stream-n one_minus_x 10)
(print-stream-n f2 10)
- SICP Exercise 연습문제 3.66 (0)2008/07/25
- SICP Exercise 연습문제 3.65 (0)2008/07/25
- SICP Exercise 연습문제 3.64 (0)2008/07/25
- SICP Exercise 연습문제 3.62 (0)2008/07/24
- SICP Exercise 연습문제 3.61 (0)2008/07/24
- SICP Exercise 연습문제 3.60 (0)2008/07/24
- SICP Exercise 연습문제 3.59 (0)2008/07/23
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